-.11=t-4.9t^2

Solution for -.11=t-4.9t^2 equation:

-.11=t-4.9t^2

We move all terms to the left:

-.11-(t-4.9t^2)=0

We add all the numbers together, and all the variables

-(t-4.9t^2)-0.11=0

We get rid of parentheses

4.9t^2-t-0.11=0

We add all the numbers together, and all the variables

4.9t^2-1t-0.11=0

a = 4.9; b = -1; c = -0.11;
Δ = b2-4ac
Δ = -12-4·4.9·(-0.11)
Δ = 3.156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{3.156}}{2*4.9}=\frac{1-\sqrt{3.156}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{3.156}}{2*4.9}=\frac{1+\sqrt{3.156}}{9.8}
$